0.0001x^2+0.02-2.5=0

Solution for 0.0001x^2+0.02-2.5=0 equation:

0.0001x^2+0.02-2.5=0

We add all the numbers together, and all the variables

0.0001x^2-2.48=0

a = 0.0001; b = 0; c = -2.48;
Δ = b2-4ac
Δ = 02-4·0.0001·(-2.48)
Δ = 0.000992
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{0.000992}}{2*0.0001}=\frac{0-\sqrt{0.000992}}{0.0002}
=-\frac{\sqrt{}}{0.0002}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{0.000992}}{2*0.0001}=\frac{0+\sqrt{0.000992}}{0.0002}
=\frac{\sqrt{}}{0.0002}
$